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#include <stdio.h>
#include <stdlib.h>
#include <errno.h>
#include <string.h>
int makeargv(const char *s, const char *delimiters, char ***argvp);
int main(int argc, char *argv[]) {
char delim[] = " \t";
int i;
char **myargv;
int numtokens;
if (argc != 2) {
fprintf(stderr, "Usage: %s string\n", argv[0]);
return 1;
}
if ((numtokens = makeargv(argv[1], delim, &myargv)) == -1) {
fprintf(stderr, "Failed to construct an argument array for %s\n", argv[1]);
return 1;
}
printf("The argument array contains:\n");
for (i = 0; i < numtokens; i++)
printf("%d:%s\n", i, myargv[i]);
return 0;
}
int makeargv(const char *s, const char *delimiters, char ***argvp) {
int error;
int i;
int numtokens;
const char *snew;
char *t;
if ((s == NULL) || (delimiters == NULL) || (argvp == NULL)) {
errno = EINVAL;
return -1;
}
*argvp = NULL;
snew = s + strspn(s, delimiters); /* snew is real start of string */
if ((t = malloc(strlen(snew) + 1)) == NULL)
return -1;
strcpy(t, snew);
numtokens = 0;
if (strtok(t, delimiters) != NULL) /* count the number of tokens in s */
for (numtokens = 1; strtok(NULL, delimiters) != NULL; numtokens++) ;
/* create argument array for ptrs to the tokens */
if ((*argvp = malloc((numtokens + 1)*sizeof(char *))) == NULL) {
error = errno;
free(t);
errno = error;
return -1;
}
/* insert pointers to tokens into the argument array */
if (numtokens == 0)
free(t);
else {
strcpy(t, snew);
**argvp = strtok(t, delimiters);
for (i = 1; i < numtokens; i++)
*((*argvp) + i) = strtok(NULL, delimiters);
}
*((*argvp) + numtokens) = NULL; /* put in final NULL pointer */
return numtokens;
}
這個程序的意思是把int main(int argc, char *argv[])
中的*argv[]參數(shù)分開，然后輸出，但是makeargv函數(shù)中的用strtok分開，
但是這個函數(shù)在的argv[1]的首地址中有“\0”的情況下就不分開了，誰能幫忙解決1下 |
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發(fā)表于 2006-08-28 19:59
