ULK2中信號(hào)量的問題

通用寄存器

請(qǐng)教給位老大：ULK2中描述信號(hào)量獲取的__down()函數(shù)時(shí)，回喚醒另一個(gè)等待進(jìn)程，如果說喚醒另一個(gè)進(jìn)程只是為了設(shè)置count和sleepers字段，那and terminates holding the semaphore這句話是什么意思？為什么要中止所持有的信號(hào)量？

原文如下：If the count field is not negative, the function sets sleepers to 0 and exits from the loop. It tries to wake up another process in the semaphore wait queue (but in our scenario, the queue is now empty) and terminates holding the semaphore. On exit, both the count field and the sleepers field are set to 0, as required when the semaphore is closed but no process is waiting for it.

xiaozhaoz

terminates holding the semaphore

這句話很清楚啊: 終止對(duì)這個(gè)信號(hào)量的占用.

通用寄存器

原帖由 xiaozhaoz 于 2006-4-13 10:44 發(fā)表
terminates holding the semaphore

這句話很清楚啊: 終止對(duì)這個(gè)信號(hào)量的占用.

還在down操作中啊，臨界區(qū)都還沒進(jìn)，怎么就中止持有信號(hào)量了呢？

通用寄存器

沉了啊，頂起來