回答一個3年前的文檔字符處理問題：附鏈接

me09

1. #!/bin/bash
   
2. while read line
   
3. do
   
4.         echo `echo $line|tr  "[ #{}]"  "\n"|awk 'BEGIN{RS="[\n]+";ORS=" "}{print $0}'`
   
5. done
   

復制代碼

cat x.txt
1. {#a#a#}
2. {#a}a#}
3. {#a#}a#}
fdss{#sdjas#}fdjsf{#dsfjs#}dfs
fdss{#sd#jas#}fdjsf{#ds#fjs#}dfs
fdss{#sdjas#fdjsf#dsfjs#}dfs
fdss{#sd#jas#}fdjsf{#ds#fjs#}dfs
fdss{#sd#jas#}fdjsf{#ds#fjs#}dfs
fdss{#sdjas#}fdjsf{#dsfjs#}dfs

運行：bash x.sh < x.txt
1. a a
2. a a
3. a a
fdss sdjas fdjsf dsfjs dfs
fdss sd jas fdjsf ds fjs dfs
fdss sdjas fdjsf dsfjs dfs
fdss sd jas fdjsf ds fjs dfs
fdss sd jas fdjsf ds fjs dfs
fdss sdjas fdjsf dsfjs dfs

個人理解這位壇友，是想把文檔處理的規(guī)整化，至少可以被AWK 規(guī)范化處理：
原帖地址http://72891.cn/thread-4130416-2-1.html
稍微修改下 就是+號鏈接版本的輸出：如下

1. #!/bin/bash
   
2. while read line
   
3. do
   
4.         echo `echo $line|tr  "[ #{}]"  "\n"|awk 'BEGIN{RS="[\n]+";ORS="+"}{print $0}'|sed 's/+$/\n/'`
   
5. done

復制代碼

cat x.txt
1. {#a#a#}
2. {#a}a#}
3. {#a#}a#}
fdss{#sdjas#}fdjsf{#dsfjs#}dfs
fdss{#sd#jas#}fdjsf{#ds#fjs#}dfs
fdss{#sdjas#fdjsf#dsfjs#}dfs
fdss{#sd#jas#}fdjsf{#ds#fjs#}dfs
fdss{#sd#jas#}fdjsf{#ds#fjs#}dfs
fdss{#sdjas#}fdjsf{#dsfjs#}dfs
------------------------------------------------------
sh x.sh < x.txt
1.+a+a
2.+a+a
3.+a+a
fdss+sdjas+fdjsf+dsfjs+dfs
fdss+sd+jas+fdjsf+ds+fjs+dfs
fdss+sdjas+fdjsf+dsfjs+dfs
fdss+sd+jas+fdjsf+ds+fjs+dfs
fdss+sd+jas+fdjsf+ds+fjs+dfs
fdss+sdjas+fdjsf+dsfjs+dfs