如何從一個txt文本中取出一個關鍵詞后的字符串

cqchengdan

請教一下，我用shell命令如何從一個txt文本中取出face_id后的字符串
我的txt文檔的內(nèi)容是：
"face_id": "1d3746e9f531c52119b9c0719ac88fef",
"position":

我現(xiàn)在想取出face_id后的1d3746e9f531c52119b9c0719ac88fef這個字符串

zsszss0000

1. echo '"face_id": "1d3746e9f531c52119b9c0719ac88fef",'  | sed 's/"//g;s/.*:\(.*\),/\1/'

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1. 
   
2. 1d3746e9f531c52119b9c0719ac88fef

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jason680

回復 1# cqchengdan

>> ...取出face_id后的字符串

What You Think Is What You Code(WYTIWYC)

$ awk -vk="face_id" -vq='"' 'match($0,q k q" *: *"q"([^"q"]+)"q,a){print a[1]}' FILE
1d3746e9f531c52119b9c0719ac88fef

$ awk 'match($0,/"face_id": "([^"]+)"/,a){print a[1]}' FILE
1d3746e9f531c52119b9c0719ac88fef

$ grep -oP '(?<="face_id": ")[^"]+' FILE
1d3746e9f531c52119b9c0719ac88fef

   

rulebook

1. grep -Po 'face_id[" :]+\K[^"]+' 1.txt

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yestreenstars

1. sed -nr 's/"face_id": "(.*)",/\1/p'

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wh7211

1. awk -F"[\"]" '$2=="face_id"{print $4}' file

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1. sed -n '/face_id/{s/^.\+ \+\"//gp}' file|sed 's/\",$//g'

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Shell_HAT

1. sed -r '/face_id/!d; s/.*"([0-9a-z]+)",/\1/' 1.txt

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reyleon

這種文本是json 格式的數(shù)據(jù)么?

九方流云

awk -F"[:]"  '/face/{$0=$2;{gsub("\"","");gsub(",","");print $0}}' file
剛開始學，不太精通，勉強看一下啊

hjfeng1988

1. [root@66a awk]# awk -F '"' '/face_id/{print $4}' file

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