這個(gè)程序老是提示有錯(cuò)誤是怎么回事�。�

mosquitoh

1. read -p "please input your damozilition date: " date2
   
2. 
   
3. date_check=$(echo $date2 | grep '[0-9]\{8\}')
   
4. if [ "$date_check" == "" ]; then
   
5.         echo "you input the wrong data format..."
   
6.         exit 1
   
7. fi
   
8. 
   
9. #declare -i date_dem=`date --date="$date2" +%s`
   
10. #declare -i date_now=`date --date="date" +%s`
    
11. #declare -i date_total_s=$(($date_dem-$date_now))
    
12. #declare -i date_d=$(($date_total_s/60/60/24))
    
13. #declare -i date_hour=$(($(($date_total_s - $date_d*24*60*60))/60/60))
    
14. #declare -i date_sec=$(($date_total_s - $date_d*24*60*60 - $date_hour*60))
    
15. #
    
16. #if [ "$date_total_s" lt "0" ]; then
    
17. #       echo "You had been demolization " $date_d " days " $date_hour " hours " $date_sec "seconds"
    
18. #else
    
19. #       echo "You will demolization after " $date_d " days " $date_hour " hours " $date_sec " seconds"
    
20. #fi
    

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剛剛寫(xiě)的，很多錯(cuò)誤，我把后面的都注釋掉了，就是前面的那一小段代碼也有問(wèn)題，求助！��！

mosquitoh

sh11.sh: 4: [: 20091223: unexpected operator

zsszss0000

我運(yùn)行就沒(méi)有問(wèn)題啊

mosquitoh

我的是ubutun 14.10，老是提示
sh11.sh: 4: [: 20091223: unexpected operator
怎么回事啊？

zsszss0000

你在第四行之前價(jià)格打印

1. echo $date_check

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看看你獲取的date_check是什么？回復(fù) 4# mosquitoh


   

mosquitoh

原來(lái)要把第四行的“==”改為“=”
求解答？？？？

zsszss0000

http://72891.cn/thread-1048907-1-1.html
根據(jù)這篇帖子，shell中的=不是賦值而是字符串比較運(yùn)算符號(hào)回復(fù) 6# mosquitoh


   

mosquitoh

謝謝了，終于調(diào)試完成運(yùn)行成功，代碼如下，和鳥(niǎo)哥寫(xiě)的做了一點(diǎn)修改，

1. read -p "please input your damozilition date: " date2
   
2. 
   
3. date_check=$(echo $date2 | grep '[0-9]\{8\}')
   
4. if [ "$date_check" = "" ]; then
   
5.         echo "you input the wrong data format..."
   
6.         exit 1
   
7. fi
   
8. 
   
9. declare -i date_dem=$(date --date="$date2" +%s)
   
10. declare -i date_now=`date +%s`
    
11. declare -i date_total_s=$(($date_dem-$date_now))
    
12. declare -i date_d=$(($date_total_s/60/60/24))
    
13. declare -i date_hour=$(($(($date_total_s - $date_d*24*60*60))/60/60))
    
14. declare -i date_min=$(($(($date_total_s - $date_d*24*60*60 - $date_hour*60*60))/60))
    
15. 
    
16. if [ "$date_total_s" -lt "0" ]; then
    
17.         echo "You had been demolization" $((-1*$date_d)) "days" $((-1*$date_hour)) "hours" $((-1*$date_min)) "minutes"
    
18. else
    
19.         echo "You will demolization after" $date_d "days" $date_hour "hours" $date_min "minutes"
    
20. fi
    

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zsszss0000

看來(lái)是這個(gè)版本的shell不支持==導(dǎo)致的問(wèn)題