如何在AWK里使用SHELL命令

251744647

現(xiàn)有一文件， 內(nèi)容如下：
#1419843842
cd /var/adm/history
#1419843843
ls
#1419843845
cd test
#1419843846
ls
#1419843846
ll
#1419843849
ll -a
#1419843883
su - root
#1419843951
exit

整個文件想要變成這樣：
Mon Dec 29 17:04:02 CST 2014 : cd /var/adm/history
Mon Dec 29 17:04:03 CST 2014 : ls
Mon Dec 29 17:04:05 CST 2014 : cd test
Mon Dec 29 17:04:06 CST 2014 : ls
Mon Dec 29 17:04:06 CST 2014 : ll
Mon Dec 29 17:04:09 CST 2014 : ll -a
Mon Dec 29 17:04:43 CST 2014 : su - root
Mon Dec 29 17:05:51 CST 2014 : exit
其實就是將＃后面的數(shù)字變成易讀的日期格式， 比如
[root@centos6 root]# date -d @1419843843
Mon Dec 29 17:04:03 CST 2014

請問如何只用AWK或者SED實現(xiàn)？謝謝！

[root@centos6 test]# awk '/#/{x=substr($0,2);y=(date -d @x);printf("%s : ", y);next}{print}' file
awk: /#/{x=substr($0,2);y=(date -d @x);print y;next}{print}
awk:                               ^ invalid char '@' in expression

jason680

回復(fù) 1# 251744647

$ awk 'sub(/^#/,"@"){cmd="date -d "$1;cmd | getline d;close(cmd);next}{print d" : "$0}' file
Mon Dec 29 17:04:02 CST 2014 : cd /var/adm/history
Mon Dec 29 17:04:03 CST 2014 : ls
Mon Dec 29 17:04:05 CST 2014 : cd test
Mon Dec 29 17:04:06 CST 2014 : ls
Mon Dec 29 17:04:06 CST 2014 : ll
Mon Dec 29 17:04:09 CST 2014 : ll -a
Mon Dec 29 17:04:43 CST 2014 : su - root
Mon Dec 29 17:05:51 CST 2014 : exit

251744647

謝謝各位啦！

bulletmarquis

回復(fù) 5# 251744647


    awk里面執(zhí)行外部外部命令，使用函數(shù)getline或system

Looiml

回復(fù) 1# 251744647

補一個sed的

1. sed -r 'N;s/#(.*)\n(.*)/echo -n $(date -d @\1) : \2/e' file

復(fù)制代碼

聆雨淋夜

回復(fù) 7# Looiml
請問結(jié)尾處的"e"是什么用法


   

Looiml

回復(fù) 8# 聆雨淋夜

e
This command allows one to pipe input from a shell command into pattern space. If a substitution was made, the command that is found in pattern space is executed and pattern space is replaced with its output. A trailing newline is suppressed; results are undefined if the command to be executed contains a nul character. This is a GNU sed extension.

簡言之，e是s命令的一個標(biāo)志，如果有替換發(fā)生，就把當(dāng)前模式空間中內(nèi)容放到shell中執(zhí)行，執(zhí)行結(jié)果送會模式空間并覆蓋之前的內(nèi)容。

Herowinter

回復(fù) 4# zooyo

新手發(fā)帖規(guī)范教程,與您老無關(guān).