本帖最后由 hgx126 于 2013-11-03 02:40 編輯
我有一gps文件如下:- A,021113,052743.159,3134.7623,N,10558.5112,E,014.0,+00.00,-10.41,+01.23;
- A,021113,052745.159,3134.7683,N,10558.5106,E,010.7,-00.61,-10.41,+00.00;
- A,021113,052745.159,3134.7683,N,10558.5106,E,010.7,-00.61,-10.41,+00.00;
- A,021113,052746.159,3134.7698,N,10558.5105,E,008.0,-01.84,-10.41,+01.23;
復(fù)制代碼 擬將第四列數(shù)據(jù)減去0.1401,將第六列數(shù)據(jù)加上0.2311,并且該兩列數(shù)據(jù)還是要保留4位小數(shù)。我用dos下的gawk處理,第4列只有2位,第六列只有1位,怎么也保留不了四位小數(shù)- gawk "BEGIN{FS=OFS=\",\"}{$4=$4-0.1401;$6=$6+0.2311;print $0}" gps.txt
復(fù)制代碼 如何保留四位小數(shù)?。請(qǐng)教大家。
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