獲取最后一個數(shù)組

atyu30

    for value in oidlist:
        result = netsnmp.snmpwalk(value, Version = 2, DestHost = "atyu30", Community = "public")
        slist.append(list(result))
        print slist



a+b+c ......

[['0.02', '0.11', '0.09']]
[['0.02', '0.11', '0.09'], ['2257']]
[['0.02', '0.11', '0.09'], ['2257'], ['1417264']]
[['0.02', '0.11', '0.09'], ['2257'], ['1417264'], ['2238014']]
[['0.02', '0.11', '0.09'], ['2257'], ['1417264'], ['2238014'], ['380180']]
[['0.02', '0.11', '0.09'], ['2257'], ['1417264'], ['2238014'], ['380180'], ['1642000']]
[['0.02', '0.11', '0.09'], ['2257'], ['1417264'], ['2238014'], ['380180'], ['1642000'], ['8167452']]
[['0.02', '0.11', '0.09'], ['2257'], ['1417264'], ['2238014'], ['380180'], ['1642000'], ['8167452'], ['5692976']]
[['0.02', '0.11', '0.09'], ['2257'], ['1417264'], ['2238014'], ['380180'], ['1642000'], ['8167452'], ['5692976'], ['48886214', '1557316605', '0', '0']]
[['0.02', '0.11', '0.09'], ['2257'], ['1417264'], ['2238014'], ['380180'], ['1642000'], ['8167452'], ['5692976'], ['48886214', '1557316605', '0', '0'], ['48886214', '526525664', '0', '0']]


需要獲取最后的那個數(shù)組

[['0.02', '0.11', '0.09'], ['2257'], ['1417264'], ['2238014'], ['380180'], ['1642000'], ['8167452'], ['5692976'], ['48886214', '1557316605', '0', '0'], ['48886214', '526525664', '0', '0']]

cdtits

循環(huán)結(jié)束時，slist 不就是最后的結(jié)果么？

atyu30

我只要最后那一個長的，前面的忽略

cdtits

貌似這時應(yīng)該是：

1. slist = [['0.02', '0.11', '0.09'], ['2257'], ['1417264'], ['2238014'], ['380180'], ['1642000'], ['8167452'], ['5692976'], ['48886214', '1557316605', '0', '0'], ['48886214', '526525664', '0', '0']]

復(fù)制代碼

atyu30

實際運行結(jié)果不是這樣的

atyu30

問題解決


    for value in oidlist:
        result = netsnmp.snmpwalk(value, Version = 2, DestHost = "10.0.20.79", Community = "public")
        slist.append(list(result))
    print slist