求組awk的處理

jxymax

有一文件有如下數(shù)據(jù)

1. public A: public n1::n2::B {

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現(xiàn)在我想要取得下面的輸出格式，請(qǐng)問應(yīng)該怎么寫

1. child=A namespace=n1::n2:: father=B

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zzy7186

awk -F '[ :]' '{print "child="$2,"namespace="$5"::"$7"::","father="$9}' d

lkk2003rty

awk '{sub(/public /,"child=";sub(/public /,"namespace=";print gensub(/(.*:([^ ]+)/,"\\1 father=\\2",'g',$0)}'

zzy7186

回復(fù) 3# lkk2003rty


    學(xué)習(xí)了 呵呵

L_kernel

1. # echo 'public A: public n1::n2::B { ' | sed -r 's/(public |private |protected )(.):/child=\2/' | sed -r 's/(public |private |protected )/namespace=/' | sed -r 's/(.) \{/ father=\1/'
   
2. child=A namespace=n1::n2:: father=B

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ilwmin

echo "public A: public n1::n2::B { " | awk -F"[ ]+" '{print "child="$2,"namespace="substr($4,0,match($4,/:[^:]+$/)),"father="substr($4,match($4,/:[^:]+$/)+1,length($4)-match($4,/:[^:]+$/))}'

jxymax

多謝大家的幫忙，已經(jīng)解決了

Gubuntu

來個(gè)Python的

1. #!/usr/bin/env python
   
2. #coding=utf-8
   
3. import re
   
4. 
   
5. s = "public A: public n1::n2::B { "
   
6. # child=A namespace=n1::n2:: father=B
   
7. 
   
8. 
   
9. t = re.search(r"public\s*(?P<child>.*):\s*public\s*(?P<namespace>(.*::.*))::(?P<father>.*)\s*{", s)
   
10. print t.group("child")
    
11. print t.group("namespace")
    
12. print t.group("father")
    

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1. A
   
2. n1::n2
   
3. B
   

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