請教如何用Sed完成，16位排版

ppshw

輸入文件

1. 0xa0,
   
2. 0xfe,
   
3. 0xea,
   
4. 0xae,
   
5. 0x12,
   
6. 0x34,
   
7. 0x22,
   
8. 0x22,
   
9. 0x45,
   
10. 0x55,
    
11. 0x93,
    
12. 0xe4,
    
13. 0xe0,

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如何用sed完成十六個一行，像uedit中二進(jìn)制模式顯示一樣

lkk2003rty

1. awk '{if(NR%16 == 0) printf "%s\n",$0; else printf "%s ",$0}' file

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bbgg1983

1. sed  -r ':a;/^.{1,75}$/{N;s/\n//;ba}' file

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where27

1. sed -r ':a;N;0~16{s/\n//g;p;d};ba' file

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bbgg1983

回復(fù) 4# where27


    貌似有問題

Shell_HAT

1. 
   
2. xargs -n 16 <urfile
   

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where27

回復(fù) 5# bbgg1983


    什么問題。。。

Shell_HAT

回復(fù) 7# where27

#cat 1.txt 0xa0, 0xfe, 0xea, 0xae, 0x12, 0x34, 0x22, 0x22, 0x45, 0x55, 0x93, 0xe4, 0xe0, #sed -r ':a;N;0~16{s/\n//g;p;d};ba' 1.txt 0xa0, 0xfe, 0xea, 0xae, 0x12, 0x34, 0x22, 0x22, 0x45, 0x55, 0x93, 0xe4, 0xe0, #cat 2.txt 0xa0, 0xfe, 0xea, 0xae, 0x12, 0x34, 0x22, 0x22, 0x45, 0x55, 0x93, 0xe4, 0xe0, 0x22, 0x45, 0x55, 0x93, 0xe4, 0xe0, #sed -r ':a;N;0~16{s/\n//g;p;d};ba' 2.txt 0xa0,0xfe,0xea,0xae,0x12,0x34,0x22,0x22,0x45,0x55,0x93,0xe4,0xe0,0x22,0x45,0x55, 0x93, 0xe4, 0xe0, #sed --version GNU sed version 4.1.5

springwind426

1. 
   
2. sed -r ':a;$!N;/^(0x..,\n?){1,7}$/{$!ba};s/(0x|,)//g;s/\n/ /g'  數(shù)據(jù)文件
   
3. 
   
4. 結(jié)果是每8行合并，同時把 0x 和 ,  都去掉，每兩個字符之間有一個空格
   

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where27

回復(fù) 8# Shell_HAT

1. sed -r ':a;N;0~16{:c;s/\n//g;p;d};$bc;ba' file

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是有問題，考慮不全，這樣就行了