對java代碼注釋的刪除

way030724

代碼注釋刪除，請高手幫忙

例如：ceshi.java

/**
* [email={@.en]{@.en[/email] Feature is father class of all the feature implementations, every feature
* hide, destroy.} [email={@.ja]{@.ja[/email] }
*
* [email={@.en]{@.en[/email] Feature is father class of all the feature implementations, every feature
* hide, destroy.} [email={@.ja]{@.ja[/email] skdjflsjdflkdjslfsjdkjflskdjfksjdlfjsldkjflksjdlkjflkjsldjflksjdsdf
* sdfdsfsdfsdfsdfsd }
*
* [email=*{@.ja]{@.ja[/email] jslkdjflkdsjlkfjldskjfkjdslfkjlsdkjflkdsjlkfjdslkjflkdsjlfkjsdlkfjslkdjflksjdlkfjsldkjfdf
* sdfsdfdsfsdfsdfsddfsdfsfdsdfsdfsdddddddddddddddddddddddddddddddddddddddd
* sdfdsfsf  }
*
* [email={@.en]{@.en[/email] Feature is father }
*
        public void hide(Hashtable paraTable) {
                currentFM.hideFeature(this, paraTable);
        }
}

規(guī)則為：1. 刪除掉 [email={@.ja]{@.ja[/email] 與 緊鄰下一個 } 和 之間的內(nèi)容，包括這之間的描述。
          2. 刪除掉 [email={@.en]{@.en[/email] 與 緊鄰下一個 } ，保留這之間的英文內(nèi)容。

希望得到的運(yùn)行結(jié)果為：

/**
* Feature is father class of all the feature implementations, every feature
* hide, destroy.
*
* [email={@Feature]Feature[/email] is father class of all the feature implementations, every feature
* hide, destroy.
*
* [email={@Feature]Feature[/email] is father
*
        public void hide(Hashtable paraTable) {
                currentFM.hideFeature(this, paraTable);
        }
}


先行謝過拉：）

way030724

帶 地址符號 '@' 問題就出錯了


下面是重發(fā)的問題:

代碼注釋刪除，請高手幫忙

例如：ceshi.java

/**
* {en Feature is father class of all the feature implementations, every fea
* hide, destroy.} {ja }
*
* {en Feature is father class of all the feature implementations, every feature
* hide, destroy.} {ja skdjflsjdflkdjslfsjdkjflskdjfksjdlfjsldkjflksjdlkjflkjsldjflksjdsdf
* sdfdsfsdfsdfsdfsd }
*
* {ja jslkdjflkdsjlkfjldskjfkjdslfkjlsdkjflkdsjlkfjdslkjflkdsjlfkjsdlkfjslkdjflksjdlkfjsldkjfdf
* sdfsdfdsfsdfsdfsddfsdfsfdsdfsdfsdddddddddddddddddddddddddddddddddddddddd
* sdfdsfsf  }
*
* {en Feature is father }
*
        public void hide(Hashtable paraTable) {
                currentFM.hideFeature(this, paraTable);
        }
}

規(guī)則為：1. 刪除掉 {ja 與 緊鄰下一個 } 和 之間的內(nèi)容，包括這之間的描述。
          2. 刪除掉 {en 與 緊鄰下一個 } ，保留這之間的英文內(nèi)容。

希望得到的運(yùn)行結(jié)果為：

/**
* Feature is father class of all the feature implementations, every feature
* hide, destroy.
*
* Feature is father class of all the feature implementations, every feature
* hide, destroy.
*
* Feature is father
*
        public void hide(Hashtable paraTable) {
                currentFM.hideFeature(this, paraTable);
        }
}


先行謝過拉：）

lululau

你這注釋怎么沒有結(jié)束的地方？

way030724

不好意思啊，我不是編寫java的，自己寫了點(diǎn)代碼，呵呵

/**
* {en Feature is father class of all the feature implementations, every fea
* hide, destroy.} {ja }
*
* {en Feature is father class of all the feature implementations, every feature
* hide, destroy.} {ja skdjflsjdflkdjslfsjdkjflskdjfksjdlfjsldkjflksjdlkjflkjsldjflksjdsdf
* sdfdsfsdfsdfsdfsd }
*
* {ja jslkdjflkdsjlkfjldskjfkjdslfkjlsdkjflkdsjlkfjdslkjflkdsjlfkjsdlkfjslkdjflksjdlkfjsldkjfdf
* sdfsdfdsfsdfsdfsddfsdfsfdsdfsdfsdddddddddddddddddddddddddddddddddddddd dd
* sdfdsfsf  }
*
* {en Feature is father }
*
**/

        public void hide(Hashtable paraTable) {
                currentFM.hideFeature(this, paraTable);
        }
}

lululau

1. 
   
2. liuxiang@MacBookPro: ~ $ echo '
   
3. /**
   
4. * {en Feature is father class of all the feature implementations, every fea
   
5. * hide, destroy.} {ja }
   
6. *
   
7. * {en Feature is father class of all the feature implementations, every feature
   
8. * hide, destroy.} {ja skdjflsjdflkdjslfsjdkjflskdjfksjdlfjsldkjflksjdlkjflkjsldjflksjdsdf
   
9. * sdfdsfsdfsdfsdfsd }
   
10. *
    
11. * {ja jslkdjflkdsjlkfjldskjfkjdslfkjlsdkjflkdsjlkfjdslkjflkdsjlfkjsdlkfjslkdjflksjdlkfjsldkjfdf
    
12. * sdfsdfdsfsdfsdfsddfsdfsfdsdfsdfsdddddddddddddddddddddddddddddddddddddddd
    
13. * sdfdsfsf  }
    
14. *
    
15. * {en Feature is father }
    
16. *
    
17.         public void hide(Hashtable paraTable) {
    
18.                 currentFM.hideFeature(this, paraTable);
    
19.         }
    
20. }' | perl -e '
    
21. > while(<>){
    
22. > $text .= $_;
    
23. > }
    
24. > $text =~ s/\{ja.*?\}//gs;
    
25. > $text =~ s/\{en(.*?)\}/$1/gs;
    
26. > print $text;'
    
27. 
    

復(fù)制代碼

試試這個，可能會有多余空行

way030724

原帖由 lululau 于 2009-6-18 21:37 發(fā)表

liuxiang@MacBookPro: ~ $ echo '
/**
* {en Feature is father class of all the feature implementations, every fea
* hide, destroy.} {ja }
*
* {en Feature is father class of all the feature i ...

比預(yù)想的只多了一行，就像{ja jdskjfkds} 如果跨行的話，只保留一行。對吧？
下面是執(zhí)行的結(jié)果，非常感謝

> print $text;'
/**
*  Feature is father class of all the feature implementations, every fea
* hide, destroy.
*
*  Feature is father class of all the feature implementations, every feature
* hide, destroy.
*
*
*
*  Feature is father
*
        public void hide(Hashtable paraTable) {
                currentFM.hideFeature(this, paraTable);
        }
}

lululau

不知道你的代碼格式規(guī)范不？
如果你能保證所有的只有一個*號的注釋行都頂在行首的話：

1. 
   
2. perl -e '
   
3. > while(<>){
   
4. > $text .= $_;
   
5. > }
   
6. > $text =~ s/\{ja.*?\}//gs;
   
7. > $text =~ s/\{en(.*?)\}/$1/gs;
   
8. > $text =~ s/(\*\s*\n)+/$1/gs;
   
9. > print $text;'
   

復(fù)制代碼

lululau

阿，不好意思，一般來說，對于正常的Java代碼，我的這個假設(shè)根本不成立阿

lululau

1. 
   
2. perl -e '
   
3. > while(<>){
   
4. > $text .= $_;
   
5. > }
   
6. > $text =~ s/\{ja.*?\}//gs;
   
7. > $text =~ s/\{en(.*?)\}/$1/gs;
   
8. > $text =~ s/([ \t]*\*\s*\n)+/$1/gs;
   
9. > print $text;'
   

復(fù)制代碼

應(yīng)該沒問題了

way030724

標(biāo)準(zhǔn)的*號 前面還有個空格的吧？ 我在試腳本，有問題了我再給你留言吧