求教各位大神怎么提取一個(gè)文件中兩個(gè)標(biāo)記之間的文本

trdcaz

回復(fù) 6# LikeLx


    請(qǐng)教下，你這里的 //!p  中 // 是什么意思�。�

roskin

trdcaz 發(fā)表于 2014-01-24 15:26
回復(fù) 9# roskin

謝謝，問(wèn)題解決了，其實(shí)是因?yàn)槲逸斎胱兞康臅r(shí)候把中括號(hào)給帶進(jìn)去了，去掉中括號(hào)就沒(méi)有問(wèn)題了

再次感謝大家�。∵@個(gè)論壇好活躍啊

LikeLx

回復(fù) 11# trdcaz
這個(gè)我還真說(shuō)不清楚，別誤導(dǎo)你！

trdcaz

回復(fù) 13# LikeLx


    還請(qǐng)不吝賜教，說(shuō)說(shuō)你是怎么理解的呢？

jackhuntcn

回復(fù) 14# trdcaz


    /regexp/
    This will select any line which matches the regular expression regexp. If regexp itself includes any / characters, each must be escaped by a backslash (\).

    The empty regular expression ‘//’ repeats the last regular expression match (the same holds if the empty regular expression is passed to the s command). Note that modifiers to regular expressions are evaluated when the regular expression is compiled, thus it is invalid to specify them together with the empty regular expression.

http://www.gnu.org/software/sed/manual/sed.html

trdcaz

回復(fù) 15# jackhuntcn


    謝謝你！// 代表的是上一次匹配的模式

elu_ligao

1. awk -va=$c -v b=$d 'index($0,a){while(getline line){if(!index(line,b)){print line >> "b"i+1".txt";close(line)}else{++i;close(line); next}}}'

復(fù)制代碼

yestreenstars

1. sed -n '/'"$c"'/,/'"$d"'/{//!p}'

復(fù)制代碼

jeffreyst

哪位大神幫忙解釋下這個(gè)語(yǔ)句？
sed -n '/begin/,/end/{//!p}'