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標(biāo)題:
libiconv轉(zhuǎn)換的字符串中不能包含字母和數(shù)字?
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作者:
Redshadows
時間:
2013-04-26 15:16
標(biāo)題:
libiconv轉(zhuǎn)換的字符串中不能包含字母和數(shù)字?
#include <iostream>
#include <bitset>
#include <iconv.h>
#include <string.h>
#include <stdio.h>
#include <error.h>
using namespace std;
bool generalIconv(const char *from, const char *to, std::string &input, std::string &output)
{
if (!from || !to)
{
cout << "from or to error" << endl;
return false;
}
if (input.size() > 60)
{
return false;
}
iconv_t conveter = iconv_open(to, from);
if ((iconv_t)-1 == conveter)
{
cout << "iconv_open fail: ";
int err = errno;
printf("%s\n", strerror(err));
return false;
}
char inBuf[48] = {}; //一個漢字的編碼最多不會超過4個字節(jié)
size_t insize = input.size() < 48? input.size(): 48;
strncpy(inBuf, input.c_str(), insize);
inBuf[insize] = 0;
char outBuf[128] = {};
size_t outsize = 128;
char *in = inBuf;
char *out = outBuf;
size_t rc = iconv(conveter, &in, &insize, &out, &outsize);
if (-1 == rc)
{
cout << "iconv fail: ";
int err = errno;
printf("%s\n", strerror(err));
return false;
}
output = std::string(outBuf);
iconv_close(conveter);
return true;
}
int main()
{
string input = "剛好12ab";
string output;
string tmp;
cout << input << endl;
if (!generalIconv("UTF-8", "UCS-2", input, output)) {
cout << "first fail" << endl;
return 1;
}
cout << input.size() << endl;
cout << output.size() << endl;
if (!generalIconv("UCS-2", "UTF-8", output, tmp)) {
cout << "first fail" << endl;
return 1;
}
cout << tmp << endl;
cout << output.size() << endl;
cout << tmp.size() << endl;
return 0;
}
復(fù)制代碼
編譯運(yùn)行:
./a.out
剛好12ab
10
4
剛好
4
6
原來字符串中的字母和數(shù)字都不見了,請問這是什么原因呢?謝謝
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