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作者:
sesame0816
時(shí)間:
2008-02-29 22:12
標(biāo)題:
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[ 本帖最后由 sesame0816 于 2014-09-27 16:30 編輯 ]
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作者:
sesame0816
時(shí)間:
2008-03-01 16:28
標(biāo)題:
回復(fù) #1 sesame0816 的帖子
th = (struct tcphdr *)(skb->data + (skb->nh.iph->ihl * 4)); 這樣就對(duì)了
但看skbuff的定義 我不知道 th = skb->h.th錯(cuò)在哪
部分skbuff的定義:
struct sk_buff {
/* These two members must be first. */
struct sk_buff *next;
struct sk_buff *prev;
struct sock *sk;
struct skb_timeval tstamp;
struct net_device *dev;
struct net_device *input_dev;
union {
struct tcphdr *th;
struct udphdr *uh;
struct icmphdr *icmph;
struct igmphdr *igmph;
struct iphdr *ipiph;
struct ipv6hdr *ipv6h;
unsigned char *raw;
} h;
union {
struct iphdr *iph;
struct ipv6hdr *ipv6h;
struct arphdr *arph;
unsigned char *raw;
} nh;
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